In the following reaction order, B is CH3 CH2 - COOH xrightarrowP/Br2 A xrightarrow[H+]alc. KOH B

Question

In the following reaction order, B is CH3 CH2 - COOH xrightarrowP/Br2 A xrightarrow[H+]alc. KOH B (A) CH2 = CH - COOH (B)  (C) CH 3 CH 2 COBr (D) CH 3 CH 2 OH .

Tardigrade Admin · Accepted Answer

P + Br2 is brominating agent that brominates the α-position. The product then undergo dehydrohalogenation in the presence of alcoholic potassium hydroxide.

Q. In the following reaction order, B is
$C H_{3} C H_{2} - COO H P / B r_{2} A a l c . K O H H^{+} B$

$C H_{2} = C H - COO H$

$C H_{3} C H_{2} COB r$

$C H_{3} C H_{2} O H .$

$P + B r_{2}$ is brominating agent that brominates the $α$ -position. The product then undergo dehydrohalogenation in the presence of alcoholic potassium hydroxide.

Q. In the following reaction order, B is CH3​CH2​−COOHP/Br2​​Aalc.KOHH+​B

CH2​=CH−COOH

CH3​CH2​COBr

CH3​CH2​OH.

P+Br2​ is brominating agent that brominates the α-position. The product then undergo dehydrohalogenation in the presence of alcoholic potassium hydroxide.

Q. In the following reaction order, B is
$C H_{3} C H_{2} - COO H P / B r_{2} A a l c . K O H H^{+} B$

$C H_{2} = C H - COO H$

$C H_{3} C H_{2} COB r$

$C H_{3} C H_{2} O H .$

$P + B r_{2}$ is brominating agent that brominates the $α$ -position. The product then undergo dehydrohalogenation in the presence of alcoholic potassium hydroxide.