In the following reaction, MnO 2+4 HCl arrow MnCl 2+2 H 2 O + Cl 2 2 moles MnO 2 react with 4 moles of HCl to form 11.2 L Cl 2 at STP. Thus, per cent yield of Cl 2 is

Question

In the following reaction, MnO 2+4 HCl arrow MnCl 2+2 H 2 O + Cl 2 2 moles MnO 2 react with 4 moles of HCl to form 11.2 L Cl 2 at STP. Thus, per cent yield of Cl 2 is (A) 25 % (B) 50 % (C) 100 % (D) 75 %

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/da88fe84133afa4f6342aa22a1510959-.png" /> But Cl 2 formed =11.2 L at STP Thus, % yield =(11.2/22.4) × 100=50 %

Q. In the following reaction,
$M n O_{2} + 4 H Cl \to M n C l_{2} + 2 H_{2} O + C l_{2}$
$2$ moles $M n O_{2}$ react with $4$ moles of $H Cl$ to form $11.2 L C l_{2}$ at STP. Thus, per cent yield of $C l_{2}$ is

$25%$

$50%$

$100%$

$75%$

But $C l_{2}$ formed $= 11.2 L$ at STP
Thus, $%$ yield $= \frac{11.2}{22.4} \times 100 = 50%$

Q. In the following reaction, MnO2​+4HCl→MnCl2​+2H2​O+Cl2​ 2 moles MnO2​ react with 4 moles of HCl to form 11.2LCl2​ at STP. Thus, per cent yield of Cl2​ is

25%

50%

100%

75%