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  4. In the following reaction, MnO 2+4 HCl arrow MnCl 2+2 H 2 O + Cl 2 2 moles MnO 2 react with 4 moles of HCl to form 11.2 L Cl 2 at STP. Thus, per cent yield of Cl 2 is

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Q. In the following reaction,
$MnO _2+4 HCl \rightarrow MnCl _2+2 H _2 O + Cl _2$
$2$ moles $MnO _2$ react with $ 4$ moles of $HCl$ to form $11.2\, L\, Cl _2$ at STP. Thus, per cent yield of $Cl _2$ is

Some Basic Concepts of Chemistry

Solution:

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But $Cl _2$ formed $=11.2 \,L$ at STP
Thus, $\%$ yield $=\frac{11.2}{22.4} \times 100=50 \%$