In the following network, the current flowing through 15 Ω resistance is

Question

In the following network, the current flowing through 15 Ω resistance is <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/17a2e3476557067223d4b31c2a1151a6-.png" /> (A) 0.8 A (B) 1.0 A (C) 1.2 A (D) 1.4 A

Tardigrade Admin · Accepted Answer

Above circuit is a balanced Wheatstone bridge. Hence, the above circuit is drawn in the following manner

From the above circuit, 18 I =24(21-1) 18 I =504-24I 24 I+18I =504 42I=504 I =(504/42) ∴ I =1.2 A

Q. In the following network, the current flowing through 15 $Ω$ resistance is

$0.8 A$

$1.0 A$

$1.2 A$

$1.4 A$

Above circuit is a balanced Wheatstone bridge.
Hence, the above circuit is drawn in the following manner

From the above circuit,
$18 I = 24 (21 - 1)$
$18 I = 504 - 24 I$
$24 I + 18 I = 504$
$42 I = 504$
$I = \frac{504}{42}$
$∴ I = 1.2 A$

Q. In the following network, the current flowing through 15 Ω resistance is

0.8A

1.0A

1.2A

1.4A