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Physics
In the following network, the current flowing through 15 Ω resistance is <img class=img-fluid question-image alt=image src=https://cdn.tardigrade.in/img/question/physics/17a2e3476557067223d4b31c2a1151a6-.png />
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Q. In the following network, the current flowing through 15 $\Omega$ resistance is
MHT CET
MHT CET 2018
Current Electricity
A
$0.8 \,A$
13%
B
$1.0 \,A$
25%
C
$1.2 \,A$
50%
D
$1.4\, A$
12%
Solution:
Above circuit is a balanced Wheatstone bridge.
Hence, the above circuit is drawn in the following manner
From the above circuit,
$18 I =24(21-1) $
$18 I =504-24I$
$24 I+18I =504 $
$42I=504 $
$I =\frac{504}{42} $
$ \therefore I =1.2 A $