Question

In the following digital circuit, what will be the output at ${}^{\prime }{Z}^{\prime },$ when the input $(A,B)$ are $(1,0),(0,0),(1,1),(0,1)$:

• A. $1,0,1,1$
• B. $0,1,0,0$
• C. $0,0,1,0$
• D. $1,1,0,1$

Answer 1

Answer: (C)

$Z=(\overline{P+R})$
$Z=(\overline{P+PQ})$
$Z=(\overline{P(1+Q)})$
$Z=(\bar{P})[$ Using Identity $(1+A)=1]$
$Z=(\overline{\overline{AB})}$
$Z=AB$
Truth table for $Z=AB$

A	B	Z
1	0	0
0	0	0
1	1	1
0	1	0