Q.
In the following digital circuit, what will be the output at $'Z',$ when the input $(A, B)$ are $(1,0), (0,0),(1,1),(0,1)$:
Solution:
$Z=(\overline{P+R})$
$Z=(\overline{P+P Q})$
$Z=(\overline{ P (1+ Q )})$
$Z=(\bar{P})[$ Using Identity $(1+A)=1]$
$Z =(\overline{\overline{ AB })}$
$Z = AB$
Truth table for $Z=A B$
A
B
Z
1
0
0
0
0
0
1
1
1
0
1
0
| A | B | Z |
|---|---|---|
| 1 | 0 | 0 |
| 0 | 0 | 0 |
| 1 | 1 | 1 |
| 0 | 1 | 0 |