Question

In the following circuit, the magnitude of current $I_1$, is _____ $A$.

Answer 1

Answer: 1

Junction law at $A$,
$\frac{x-(y+5)}{1}+\frac{x-2}{2}+\frac{x-0}{2}=0$....(1)
Junction law at $B$,
$\frac{y+5-x}{1}+\frac{y-0}{1}+\frac{y-2}{1}=0$....(2)
On solving equation (1) and Equation (2) $x=3$
$\&y=0$
At $D$ junction
$I_1=i_1+i_2$
$I_1=\frac{y-0}{1}+\frac{x-0}{2}$
$=\frac{0-0}{1}+\frac{3-0}{2}$
$I_1=15A$