Junction law at $A$,
$\frac{x-(y+5)}{1}+\frac{x-2}{2}+\frac{x-0}{2}=0$....(1)
Junction law at $B$,
$\frac{ y +5- x }{1}+\frac{ y -0}{1}+\frac{ y -2}{1}=0$....(2)
On solving equation (1) and Equation (2) $x =3$
$\& y =0$
At $D$ junction
$I _1 = i _1+ i _2 $
$I _1 =\frac{ y -0}{1}+\frac{ x -0}{2}$
$ =\frac{0-0}{1}+\frac{3-0}{2} $
$I _1 =15 A$