In the final answer of the expression ((29.2-20.2)(1.79 × 105)/1.37) . The number of significant figures is

Question

In the final answer of the expression ((29.2-20.2)(1.79 × 105)/1.37) . The number of significant figures is (A) 1 (B) 2 (C) 3 (D) 4

Tardigrade Admin · Accepted Answer

((29.2-20.2)(1.79 × 105)/1.37)=(9.0 × 1.79 × 105/1.37) Least precise terms i.e., 9.0 has only two significant figures. Hence, final answer will have two significant figures.

Q. In the final answer of the expression $\frac{( 29.2 - 20.2 ) ( 1.79 \times 1 0 ^{5} )}{1.37} .$ The number of significant figures is

1

2

3

4

$\frac{( 29.2 - 20.2 ) ( 1.79 \times 1 0 ^{5} )}{1.37} = \frac{9.0 \times 1.79 \times 1 0 ^{5}}{1.37}$

Least precise terms i.e., $9.0$ has only two significant figures. Hence, final answer will have two significant figures.

Q. In the final answer of the expression 1.37(29.2−20.2)(1.79×105)​. The number of significant figures is

1

2

3

4

1.37(29.2−20.2)(1.79×105)​=1.379.0×1.79×105​ Least precise terms i.e., 9.0 has only two significant figures. Hence, final answer will have two significant figures.

Q. In the final answer of the expression $\frac{( 29.2 - 20.2 ) ( 1.79 \times 1 0 ^{5} )}{1.37} .$ The number of significant figures is

$\frac{( 29.2 - 20.2 ) ( 1.79 \times 1 0 ^{5} )}{1.37} = \frac{9.0 \times 1.79 \times 1 0 ^{5}}{1.37}$

Least precise terms i.e., $9.0$ has only two significant figures. Hence, final answer will have two significant figures.