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  4. In the final answer of the expression ((29.2-20.2)(1.79 × 105)/1.37) . The number of significant figures is

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Q. In the final answer of the expression $\frac{(29.2-20.2)\left(1.79 \times 10^{5}\right)}{1.37} .$ The number of significant figures is

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Solution:

$\frac{(29.2-20.2)\left(1.79 \times 10^{5}\right)}{1.37}=\frac{9.0 \times 1.79 \times 10^{5}}{1.37}$

Least precise terms i.e., $9.0$ has only two significant figures. Hence, final answer will have two significant figures.