In the figure, the equivalent capacitance between A and B is

Question

In the figure, the equivalent capacitance between A and B is (A)  3.75 μ F (B)  5.25 μ F (C)  6.5 μ F (D)  10.5 μ F

Tardigrade Admin · Accepted Answer

The circuit can be simplified as shown. lt is a balanced Wheatstone bridge. ⇒ CAB = (5 × 3/ 5 + 3) + (5 × 3/5 + 3) ⇒ CAB = 2 × (15/8) = (30/8) = 3.75 μ F

Q. In the figure, the equivalent capacitance between A and B is

$3.75 μ F$

$5.25 μ F$

$6.5 μ F$

$10.5 μ F$

The circuit can be simplified as shown.
lt is a balanced Wheatstone bridge.
$\Rightarrow C_{A B} = \frac{5 \times 3}{5 + 3} + \frac{5 \times 3}{5 + 3}$
$\Rightarrow C_{A B} = 2 \times \frac{15}{8} = \frac{30}{8} = 3.75 μ F$

Q. In the figure, the equivalent capacitance between A and B is

3.75μF

5.25μF

6.5μF

10.5μF

The circuit can be simplified as shown. lt is a balanced Wheatstone bridge. ⇒CAB​=5+35×3​+5+35×3​ ⇒CAB​=2×815​=830​=3.75μF

$3.75 μ F$

$5.25 μ F$

$6.5 μ F$

$10.5 μ F$

The circuit can be simplified as shown.
lt is a balanced Wheatstone bridge.
$\Rightarrow C_{A B} = \frac{5 \times 3}{5 + 3} + \frac{5 \times 3}{5 + 3}$
$\Rightarrow C_{A B} = 2 \times \frac{15}{8} = \frac{30}{8} = 3.75 μ F$