Q.
In the figure, the equivalent capacitance between A and B is
Electrostatic Potential and Capacitance
Solution:
The circuit can be simplified as shown.
lt is a balanced Wheatstone bridge.
$\Rightarrow \, \, \, \, \, {C_{AB}} = \frac {5 \times 3}{ 5 + 3} + \frac {5 \times 3}{5 + 3}$
$\Rightarrow \, \, \, \, \, {C_{AB}} = 2 \times \frac {15}{8} = \frac {30}{8} = 3.75 \mu F$
