In the figure shown, the capacity of the condenser C is 2 μ F. If the circuit is in steady state, the current in 2 Ω resistor is

Question

In the figure shown, the capacity of the condenser C is 2 μ F. If the circuit is in steady state, the current in 2 Ω resistor is (A) 9 A (B) 0.9 A (C) (1/9) A (D) (1/0.9) A

Tardigrade Admin · Accepted Answer

No current flows through the capacitor branch in steady state. Total current supplied by the battery, i=(6/2.8+1.2)=(3/2) Current through 2 Ω resistor =(3/2) × (3/5)=0.9 A

Q. In the figure shown, the capacity of the condenser $C$ is $2 μ F$ . If the circuit is in steady state, the current in $2 Ω$ resistor is

9 A

0.9 A

$\frac{1}{9} A$

$\frac{1}{0.9} A$

No current flows through the capacitor branch in steady state. Total current supplied by the battery,
$i = \frac{6}{2.8 + 1.2} = \frac{3}{2}$
Current through $2 Ω$ resistor $= \frac{3}{2} \times \frac{3}{5} = 0.9 A$

Q. In the figure shown, the capacity of the condenser C is 2μF. If the circuit is in steady state, the current in 2Ω resistor is

9 A

0.9 A

91​A

0.91​A

No current flows through the capacitor branch in steady state. Total current supplied by the battery, i=2.8+1.26​=23​ Current through 2Ω resistor =23​×53​=0.9A

Q. In the figure shown, the capacity of the condenser $C$ is $2 μ F$ . If the circuit is in steady state, the current in $2 Ω$ resistor is

$\frac{1}{9} A$

$\frac{1}{0.9} A$

No current flows through the capacitor branch in steady state. Total current supplied by the battery,
$i = \frac{6}{2.8 + 1.2} = \frac{3}{2}$
Current through $2 Ω$ resistor $= \frac{3}{2} \times \frac{3}{5} = 0.9 A$