Thank you for reporting, we will resolve it shortly
Q.
In the figure shown, the capacity of the condenser $C$ is $2\, \mu F$. If the circuit is in steady state, the current in $2\, \Omega$ resistor is
Current Electricity
Solution:
No current flows through the capacitor branch in steady state. Total current supplied by the battery,
$i=\frac{6}{2.8+1.2}=\frac{3}{2}$
Current through $2 \, \Omega$ resistor $=\frac{3}{2} \times \frac{3}{5}=0.9\, A$
