In the figure shown below, the terminal voltage across E2 is

Question

In the figure shown below, the terminal voltage across E2 is (A) 12 V (B) 12.66 V (C) 11.34 V (D) 11.66 V

Tardigrade Admin · Accepted Answer

Net voltage =12-8=4 text V Net resistance =9+2+1=12 Ω Current through the circuit =(4/12)=(1/3)A Terminal voltage across E2 is =E2-Ir2=12-(1/3)× 2 =12-(2/3)=(34/3)=11.34 V

Q. In the figure shown below, the terminal voltage across $E_{2}$ is

12 V

12.66 V

11.34 V

11.66 V

12.33 V

Net voltage $= 12 - 8 = 4 V$
Net resistance $= 9 + 2 + 1 = 12 Ω$
Current through the circuit
$= \frac{4}{12} = \frac{1}{3} A$
Terminal voltage across
$E_{2}$ is $= E_{2} - I r_{2} = 12 - \frac{1}{3} \times 2$
$= 12 - \frac{2}{3} = \frac{34}{3} = 11.34 V$

Q. In the figure shown below, the terminal voltage across E2​ is