Question

In the figure shown below, the terminal voltage across $ {{E}_{2}} $ is

• A. 12 V
• B. 12.66 V
• C. 11.34 V
• D. 11.66 V
• E. 12.33 V

Answer 1

Answer: (C)

Net voltage $ =12-8=4\text{ }V $
Net resistance $ =9+2+1=12\,\Omega $
Current through the circuit
$ =\frac{4}{12}=\frac{1}{3}A $
Terminal voltage across
$ {{E}_{2}} $ is $ ={{E}_{2}}-I{{r}_{2}}=12-\frac{1}{3}\times 2 $
$ =12-\frac{2}{3}=\frac{34}{3}=11.34\,V $