In the figure shown below, the charge on the left plate of the 10μ F capacitor is-30μ C. The charge (in μ C) on the right plate of the 6μ F capacitor is:

Question

In the figure shown below, the charge on the left plate of the 10μ F capacitor is-30μ C. The charge (in μ C) on the right plate of the 6μ F capacitor is: <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/d516e6d47fb4ebc7311055b0d3eba19d-.png" /> (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/40c36a211a80a201c1a9260bbc9e1c29-.png" /> As given in the figure, 6μ F and 4μ F are in parallel. Now using charge conservation Charge on 6μ F capacitor=(6/6 +4) ×30 = 18μ C Since charge is asked on right plate therefore is +18μ C

Q. In the figure shown below, the charge on the left plate of the $10 μ F$ capacitor is $- 30 μ C$ . The charge $(in μ C)$ on the right plate of the $6 μ F$ capacitor is:

As given in the figure, $6 μ F$ and $4 μ F$ are in parallel. Now using charge conservation
Charge on $6 μ F$ capacitor $= \frac{6}{6 + 4} \times 30$
$= 18 μ C$
Since charge is asked on right plate therefore is $+ 18 μ C$

Q. In the figure shown below, the charge on the left plate of the 10μF capacitor is−30μC. The charge (inμC) on the right plate of the 6μF capacitor is:

As given in the figure, 6μF and 4μF are in parallel. Now using charge conservation Charge on 6μF capacitor=6+46​×30 =18μC Since charge is asked on right plate therefore is +18μC

Q. In the figure shown below, the charge on the left plate of the $10 μ F$ capacitor is $- 30 μ C$ . The charge $(in μ C)$ on the right plate of the $6 μ F$ capacitor is:

As given in the figure, $6 μ F$ and $4 μ F$ are in parallel. Now using charge conservation
Charge on $6 μ F$ capacitor $= \frac{6}{6 + 4} \times 30$
$= 18 μ C$
Since charge is asked on right plate therefore is $+ 18 μ C$