Question

In the figure shown below, the charge on the left plate of the $10\mu F$ capacitor is$-30\mu C$. The charge $\left(in \,\mu C\right)$ on the right plate of the $6\mu F$ capacitor is:

Answer 1

As given in the figure, $6\mu F$ and $4\mu F$ are in parallel. Now using charge conservation
Charge on $6\mu F$ capacitor$=\frac{6}{6 +4} \times30$
$= 18\mu C$
Since charge is asked on right plate therefore is $ +18\mu C$