In the figure, a ball of mass m is tied with two strings of equal length as shown. If the rod is rotated with angular velocity ω, then

Question

In the figure, a ball of mass m is tied with two strings of equal length as shown. If the rod is rotated with angular velocity ω, then (A) T1 >T2 (B) T2 >T1 (C) T1=T2 (D) T1=(T2/6)

Tardigrade Admin · Accepted Answer

For vertical equilibrium T1 cos θ=m g +T2 cos θ T1=(m g/ cos θ)+T2 θ < 90° so cos θ > 0 ⇒ T1 >T2

Q. In the figure, a ball of mass $m$ is tied with two strings of equal length as shown. If the rod is rotated with angular velocity $ω$ , then

$T_{1} > T_{2}$

$T_{2} > T_{1}$

$T_{1} = T_{2}$

$T_{1} = \frac{T _{2}}{6}$

For vertical equilibrium
$T_{1} cos θ = m g + T_{2} cos θ$
$T_{1} = \frac{m g}{c o s θ} + T_{2}$
$θ < 9 0^{\circ}$ so $cos θ > 0$
$\Rightarrow T_{1} > T_{2}$

Q. In the figure, a ball of mass m is tied with two strings of equal length as shown. If the rod is rotated with angular velocity ω, then

T1​>T2​

T2​>T1​

T1​=T2​

T1​=6T2​​