Q.
In the figure, a ball of mass $m$ is tied with two strings of equal length as shown. If the rod is rotated with angular velocity $\omega$, then
Laws of Motion
Solution:
For vertical equilibrium
$T_{1} \cos \theta=m g +T_{2} \cos \theta$
$T_{1}=\frac{m g}{\cos \theta}+T_{2}$
$\theta < 90^{\circ}$ so $\cos \theta > 0$
$\Rightarrow T_{1} >T_{2}$
