In the equation H2S+2HNO3 → 2H2O+2NO2+S. The equivalent weight of hydrogen sulphide is:

Question

In the equation H2S+2HNO3 → 2H2O+2NO2+S. The equivalent weight of hydrogen sulphide is: (A) 18 (B) 68 (C) 34 (D) 17

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/ca823e1b748e0150fedc6638cd7c1ec5-.png" /> Hence, the equivalent weight of H2S = ( textmolecular weight/ textchange in oxidation number) = (34/2) = 17

Q. In the equation $H_{2} S + 2 H N O_{3} \to 2 H_{2} O + 2 N O_{2} + S .$ The equivalent weight of hydrogen sulphide is:

18

68

34

17

Hence, the equivalent weight of
$H_{2} S = \frac{molecular weight}{change in oxidation number} = \frac{34}{2} = 17$

Q. In the equation H2​S+2HNO3​→2H2​O+2NO2​+S. The equivalent weight of hydrogen sulphide is:

18

68

34

17

Hence, the equivalent weight of H2​S=change in oxidation numbermolecular weight​=234​=17

Q. In the equation $H_{2} S + 2 H N O_{3} \to 2 H_{2} O + 2 N O_{2} + S .$ The equivalent weight of hydrogen sulphide is:

Hence, the equivalent weight of
$H_{2} S = \frac{molecular weight}{change in oxidation number} = \frac{34}{2} = 17$