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  4. In the equation H2S+2HNO3 → 2H2O+2NO2+S. The equivalent weight of hydrogen sulphide is:

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Q. In the equation $ {{H}_{2}}S+2HN{{O}_{3}} \to 2{{H}_{2}}O+2N{{O}_{2}}+S. $ The equivalent weight of hydrogen sulphide is:

Bihar CECEBihar CECE 2006Redox Reactions

Solution:

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Hence, the equivalent weight of
$H_2S = \frac{\text{molecular weight}}{\text{change in oxidation number}} = \frac{34}{2} = 17$