In the electrolysis of acidulated water, it is desired to obtain 1.12 cc of Hydrogen per second under S.T.P. condition. The current to be passed is

Question

In the electrolysis of acidulated water, it is desired to obtain 1.12 cc of Hydrogen per second under S.T.P. condition. The current to be passed is (A) 19.3 Amp (B) 0.965 Amp (C) 1.93 Amp (D) 9.65 Amp

Tardigrade Admin · Accepted Answer

No. of moles of H 2=(1.12/22400) No. of equivalence of hydrogen =(1.12 × 2/22400)=10-4 No. of Faradays required =10-4 ∴ Current to be passed in one second =96500 × 10-4 =9.65 A

Q. In the electrolysis of acidulated water, it is desired to obtain $1.12 cc$ of Hydrogen per second under $S . T . P .$ condition. The current to be passed is

$19.3 A m p$

$0.965 A m p$

$1.93 A m p$

$9.65 A m p$

No. of moles of $H_{2} = \frac{1.12}{22400}$

No. of equivalence of hydrogen

$= \frac{1.12 \times 2}{22400} = 1 0^{- 4}$

No. of Faradays required $= 1 0^{- 4}$

$∴$ Current to be passed in one second

$= 96500 \times 1 0^{- 4}$

$= 9.65 A$

Q. In the electrolysis of acidulated water, it is desired to obtain 1.12cc of Hydrogen per second under S.T.P. condition. The current to be passed is

19.3Amp

0.965Amp

1.93Amp

9.65Amp