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Q. In the electrolysis of acidulated water, it is desired to obtain $1.12\, cc$ of Hydrogen per second under $S.T.P.$ condition. The current to be passed is

KCETKCET 2009Electrochemistry

Solution:

No. of moles of $H _{2}=\frac{1.12}{22400}$

No. of equivalence of hydrogen

$=\frac{1.12 \times 2}{22400}=10^{-4}$

No. of Faradays required $=10^{-4}$

$\therefore \,\,\,$ Current to be passed in one second

$=96500 \times 10^{-4} $

$=9.65\, A$