Question

In the diffraction pattern due to a single slit linear width of the central max will be twice that of slit width $(d)$. The distance between the slit and the screen is

• A. $\frac{{\lambda }^2}{d}$
• B. $\frac{d^2}{\lambda }$
• C. $\frac{2{\lambda }^2}{d}$
• D. $\frac{2d^2}{\lambda }$

Answer 1

Answer: (B)

Width of central maxima due to single slit diffraction is given by,
$\beta =\frac{2\lambda D}{d}$
Here, $\beta =2d$
So, $2d=\frac{2\lambda D}{d}$ or $D=\frac{d^2}{\lambda }$