In the diagram shown, the difference in the two tubes of the manometer is 5 cm, the cross section of the tube at A and B is 6 mm2 and 10 mm2 respectively. The rate at which water flows through the tube is (g = 10 ms-2)

Question

In the diagram shown, the difference in the two tubes of the manometer is 5 cm, the cross section of the tube at A and B is 6 mm2 and 10 mm2 respectively. The rate at which water flows through the tube is (g = 10 ms-2) (A) 7.5 cc/s (B) 8.0 cc/s (C) 10.0 cc/s (D) 12.5 cc/s

Tardigrade Admin · Accepted Answer

Q = A 1 A 2 √(2 g ( h 1- h 2)/( A 12- A 22)) =6 × 10 × 10-4 √(2 × 980(5)/(-36+100) × 10-2) =6 × 10-3 √(9800 × 102/64) =(6 × 10-3 × 1000/8)=7.5

Q. In the diagram shown, the difference in the two tubes of the manometer is $5 c m$ , the cross section of the tube at $A$ and $B$ is $6 m m^{2}$ and $10 m m^{2}$ respectively. The rate at which water flows through the tube is ( $g = 10 m s^{- 2}$ )

7.5 cc/s

8.0 cc/s

10.0 cc/s

12.5 cc/s

$Q = A_{1} A_{2} \frac{2 g ( h _{1} - h _{2} )}{( A _{1}^{2} - A _{2}^{2} )}$
$= 6 \times 10 \times 1 0^{- 4} \frac{2 \times 980 ( 5 )}{( - 36 + 100 ) \times 1 0 ^{- 2}}$
$= 6 \times 1 0^{- 3} \frac{9800 \times 1 0 ^{2}}{64}$
$= \frac{6 \times 1 0 ^{- 3} \times 1000}{8} = 7.5$

Q. In the diagram shown, the difference in the two tubes of the manometer is 5cm, the cross section of the tube at A and B is 6mm2 and 10mm2 respectively. The rate at which water flows through the tube is (g=10ms−2)