Question

In the circuit shown, the current through the $5\Omega$ resistor is

• A. $\frac{8}{3}A$
• B. $\frac{9}{13}A$
• C. $\frac{4}{13}A$
• D. $\frac{1}{3}A$
• E. $\frac{2}{3}A$

Answer 1

Answer: (D)

$\frac{1}{R}=\frac{1}{2}+\frac{1}{2}=1$
$R=1\Omega$ Total resistance
$=R+5=1+5=6\Omega$
$E_{eff}=\frac{E_1{r}_1+E_2{r}_2}{r_1+r_2}=\frac{2\times 2+2\times 2}{2+2}$
$=2V$
$i=\frac{E_{ff}}{R}=\frac{2}{6}=\frac{1}{3}A$