In the circuit shown, switch is connected to position 1 for a very long time. What is maximum current (in ampere) through the inductor when switch is taken to position 2?

Question

In the circuit shown, switch is connected to position 1 for a very long time. What is maximum current (in ampere) through the inductor when switch is taken to position 2? (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

(1/2) C V2=(1/2) L I2 I=V √(C/L)=6 √(50 × 10-6/8 × 10-4)=1.5 A

Q. In the circuit shown, switch is connected to position $1$ for a very long time. What is maximum current (in ampere) through the inductor when switch is taken to position $2$ ?

$\frac{1}{2} C V^{2} = \frac{1}{2} L I^{2}$
$I = V \frac{C}{L} = 6 \frac{50 \times 1 0 ^{- 6}}{8 \times 1 0 ^{- 4}} = 1.5 A$

Q. In the circuit shown, switch is connected to position 1 for a very long time. What is maximum current (in ampere) through the inductor when switch is taken to position 2?

21​CV2=21​LI2 I=VLC​​=68×10−450×10−6​​=1.5A

Q. In the circuit shown, switch is connected to position $1$ for a very long time. What is maximum current (in ampere) through the inductor when switch is taken to position $2$ ?

$\frac{1}{2} C V^{2} = \frac{1}{2} L I^{2}$
$I = V \frac{C}{L} = 6 \frac{50 \times 1 0 ^{- 6}}{8 \times 1 0 ^{- 4}} = 1.5 A$