Question

In the circuit shown, switch is connected to position $1$ for a very long time. What is maximum current (in ampere) through the inductor when switch is taken to position $2$?

Answer 1

$\frac{1}{2} C V^{2}=\frac{1}{2} L I^{2}$
$I=V \sqrt{\frac{C}{L}}=6 \sqrt{\frac{50 \times 10^{-6}}{8 \times 10^{-4}}}=1.5\, A$