In the circuit shown in the figure, the potential difference across the 4.5 μ F capacitor is

Question

In the circuit shown in the figure, the potential difference across the 4.5 μ F capacitor is (A) (8/3) volts (B) 4 volts (C) 6 volts (D) 8 volts

Tardigrade Admin · Accepted Answer

The given circuit can be redrawn as follows: Potential difference across 4.5 μ F capacitor <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/49712f17d547dd3316689073abb95b70-.png" /> V=(9/((9)2+9)) × 12=8 V

Q. In the circuit shown in the figure, the potential difference across the $4.5 μ F$ capacitor is

$\frac{8}{3}$ volts

4 volts

6 volts

8 volts

The given circuit can be redrawn as follows:
Potential difference across $4.5 μ F$ capacitor

$V = \frac{9}{( \frac{9}{2} + 9 )} \times 12 = 8 V$

Q. In the circuit shown in the figure, the potential difference across the 4.5μF capacitor is

38​ volts