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Q.
In the circuit shown in the figure, the potential difference across the $4.5\, \mu F$ capacitor is
Electrostatic Potential and Capacitance
Solution:
The given circuit can be redrawn as follows:
Potential difference across $4.5\, \mu F$ capacitor
$V=\frac{9}{\left(\frac{9}{2}+9\right)} \times 12=8\, V$