In the circuit shown in the figure K 1 is open. The charge on capacitor C in steady state is q 1. Now key is closed and at steady state charge on C is q 2. The ratio of charges q 1 / q 2 is

Question

In the circuit shown in the figure K 1 is open. The charge on capacitor C in steady state is q 1. Now key is closed and at steady state charge on C is q 2. The ratio of charges q 1 / q 2 is (A) 5/3 (B) 3/5 (C) 1 (D) 2/3

Tardigrade Admin · Accepted Answer

q 1= CE q 2= C × ( E /2+3) × 3 = CE × (3/5)

Q. In the circuit shown in the figure $K_{1}$ is open. The charge on capacitor $C$ in steady state is $q_{1}$ . Now key is closed and at steady state charge on $C$ is $q_{2}$ . The ratio of charges $q_{1} / q_{2}$ is

5/3

3/5

1

2/3

$q_{1} = CE$
$q_{2} = C \times \frac{E}{2 + 3} \times 3$
$= CE \times \frac{3}{5}$

Q. In the circuit shown in the figure K1​ is open. The charge on capacitor C in steady state is q1​. Now key is closed and at steady state charge on C is q2​. The ratio of charges q1​/q2​ is

5/3

3/5

1

2/3

q1​=CE q2​=C×2+3E​×3 =CE×53​

Q. In the circuit shown in the figure $K_{1}$ is open. The charge on capacitor $C$ in steady state is $q_{1}$ . Now key is closed and at steady state charge on $C$ is $q_{2}$ . The ratio of charges $q_{1} / q_{2}$ is

$q_{1} = CE$
$q_{2} = C \times \frac{E}{2 + 3} \times 3$
$= CE \times \frac{3}{5}$