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  4. In the circuit shown in the figure K 1 is open. The charge on capacitor C in steady state is q 1. Now key is closed and at steady state charge on C is q 2. The ratio of charges q 1 / q 2 is

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Q. In the circuit shown in the figure $K _{1}$ is open. The charge on capacitor $C$ in steady state is $q _{1}$. Now key is closed and at steady state charge on $C$ is $q _{2}$. The ratio of charges $q _{1} / q _{2}$ isPhysics Question Image

Solution:

$q _{1}= CE$
$q _{2}= C \times \frac{ E }{2+3} \times 3$
$= CE \times \frac{3}{5}$