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Tardigrade
Question
Physics
In the circuit shown in figure, power developed across 1 Ω, 2 Ω and 3 Ω resistances are in the ratio.
Q. In the circuit shown in figure, power developed across
1
Ω
,
2
Ω
and
3
Ω
resistances are in the ratio.
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A
1 : 2 : 3
B
4 : 2 : 27
C
6 : 4 : 9
D
2 : 1 : 27
Solution:
Current distribution is as shown in figure
∴
Powers are
P
1
=
I
1
2
R
1
=
9
4
i
2
,
P
2
=
I
2
2
R
2
=
9
2
i
2
,
and
P
3
=
I
3
2
R
3
=
3
i
2
=
9
27
i
2
⇒
P
1
:
P
2
:
P
3
::
4
:
2
:
27