Current distribution is as shown in figure
$\therefore $ Powers are
$P_{1}=I_{1}^{2} R_{1}=\frac{4}{9} i^{2},$
$P_{2}=I_{2}^{2} R_{2}=\frac{2}{9} i^{2}$,
and $P_{3}=I_{3}^{2} R_{3}=3 i^{2}$
$=\frac{27}{9} i^{2}$
$\Rightarrow \, P_{1}: P_{2}: P_{3}:: 4: 2: 27$