Question

In the circuit shown in figure, calculate the charge stored (in $\mu C$ ) in $5\mu F$ capacitor in steady state.

Answer 1

Answer: 700

We distribute the potentials in the circuit shown in figure below

Writing nodal equation for $x$ gives
$10x+5(x+200)+5(x+150)=0$
$\Rightarrow 4x=-350\Rightarrow x=-70V$
Thus charge on $10\mu F$ capacitor is given as
$q_{10\mu F}=10\times 70=700\mu C$