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Q.
In the circuit shown in figure, calculate the charge stored (in $\mu C$ ) in $5\, \mu F$ capacitor in steady state.
Electrostatic Potential and Capacitance
Solution:
We distribute the potentials in the circuit shown in figure below
Writing nodal equation for $x$ gives
$ 10 x+5(x+200)+5(x+150)=0 $
$\Rightarrow 4 x=-350 \Rightarrow x=-70\, V$
Thus charge on $10\, \mu F$ capacitor is given as
$q_{10\, \mu F }=10 \times 70=700\, \mu C$
