Question

In the circuit shown in figure

• A. power supplied by the battery is $200W$
• B. current flowing in the circuit is $5A$
• C. Potential difference across the $4\Omega$ resistance is equal to the potential difference across the $6\Omega$ resistance
• D. current in wire $AB$ is zero

Answer 1

Answer: (A), (C)

$4\Omega$ and $6\Omega$ resistor are short-circuited. Therefore, no current will flow through these resistance. Current passing through the battery is $I=(20/2)=10A$
This is also the current passing in wire $AB$ from $B$ to $A$. Power supplied by the battery
$P=EI=(20)(10)=200W$
Potential difference across the $4\Omega$ resistance $=$ Potential difference across the $6\Omega$ resistance.