Question

In the circuit shown in figure

• A. power supplied by the battery is $200 W$
• B. current flowing in the circuit is $5 A$
• C. Potential difference across the $4 \Omega$ resistance is equal to the potential difference across the $6 \Omega$ resistance
• D. current in wire $A B$ is zero

Answer 1

Answer: (A), (C)

$ 4 \Omega$ and $6 \Omega$ resistor are short-circuited. Therefore, no current will flow through these resistance. Current passing through the battery is $I=(20 / 2)=10 A$
This is also the current passing in wire $A B$ from $B$ to $A$. Power supplied by the battery
$P=E I=(20)(10)=200 W$
Potential difference across the $4 \Omega$ resistance $=$ Potential difference across the $6 \Omega$ resistance.