Question

In the circuit shown in Fig, the current in $4\Omega$ resistance is $1.2A$. What is the potential difference (in volt) between $B$ and $C$?

Answer 1

Answer: 3.6

The potential difference across $4\Omega$ resistance is given by
$V=4\times i_1=4\times 1.2=4.8$ volt
So, the potential across $8\Omega$ resistance is also $4.8$ volt.
Current $i_2=\frac{V}{8}=\frac{4.8}{8}=0.6$ amp
Current in $2\Omega$ resistance $i=i_1+i_2$
$\therefore i=1.2+0.6=1.8$ amp
Potential difference across $2\Omega$ resistance
$V_{BC}=1.8\times 2=3.6$ volts