Thank you for reporting, we will resolve it shortly
Q.
In the circuit shown in Fig, the current in $4 \,\Omega$ resistance is $ 1.2 \,A$. What is the potential difference (in volt) between $B$ and $C$?
Current Electricity
Solution:
The potential difference across $4\Omega$ resistance is given by
$ V = 4 \times i_1 = 4 \times 1.2 = 4.8$ volt
So, the potential across $8\Omega$ resistance is also $4.8$ volt.
Current $i_2 = \frac{V}{8} = \frac{4.8}{8} = 0.6 $ amp
Current in $2\Omega$ resistance $i = i_1 + i_2$
$\therefore i= 1.2 + 0.6= 1.8$ amp
Potential difference across $2\Omega$ resistance
$V_{BC} = 1.8 \times 2 = 3.6$ volts
