Question

In the circuit shown below what will be the readings of the voltmeter and ammeter? (Total impedance of circuit $Z=100\Omega$ )

• A. 200 V, 1 A
• B. 800 V, 2 A
• C. 100 V,2A
• D. 220 V, 2.2 A

Answer 1

Answer: (D)

In the series L-C-R circuit $V_R$
(voltage across resistance) is in the phase with current (i), while
$V_C$ (voltage across inductance) leads
$i$ by ${90}^o,$ while $V_C$ lags behind
$i$ by ${90}^o.$
Resultant emf E is
$E^2=V_R^2+{(V_L-V_C)}^2$
Since, $V_L=V_C=300V$
$\therefore$ $E=V_R=220V$
Reading of ammeter,
$i=\frac{E}{R}=\frac{220}{100}=2.2A$