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Q.
In the circuit shown below what will be the readings of the voltmeter and ammeter? (Total impedance of circuit $ Z=100\,\Omega $ )
Jharkhand CECEJharkhand CECE 2010
Solution:
In the series L-C-R circuit $ {{V}_{R}} $
(voltage across resistance) is in the phase with current (i), while
$ {{V}_{C}} $ (voltage across inductance) leads
$ i $ by $ {{90}^{o}}, $ while $ {{V}_{C}} $ lags behind
$ i $ by $ {{90}^{o}}. $
Resultant emf E is
$ {{E}^{2}}=V_{R}^{2}+{{({{V}_{L}}-{{V}_{C}})}^{2}} $
Since, $ {{V}_{L}}={{V}_{C}}=300\,V $
$ \therefore $ $ E={{V}_{R}}=220\,V $
Reading of ammeter,
$ i=\frac{E}{R}=\frac{220}{100}=2.2A $
