Question

In the circuit shown below, the current in the $1\Omega$ resistor is

• A. 1.3 A, from/5to Q
• B. 0.13 A, from Q to P
• C. 0 A
• D. 0.13 A, from/5to Q

Answer 1

Answer: (B)

Applying Kirchhoff's loop law in loops 1 and 2 in the directions shown in figure we have
$6-3(i_1+i_2)-i_2=0$
......(i) $9-2i_1+i_2-3i_1=0$
.......(ii) Solving Eqs. (i) and (ii) we get,
$i_2=0.13A$
Hence, the current in 1 Q resister is 0.13 A from Q to P