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Q. In the circuit shown below, the current in the $1\Omega$ resistor isPhysics Question Image

AIPMTAIPMT 1988Current Electricity

Solution:

Applying Kirchhoff's loop law in loops 1 and 2 in the directions shown in figure we have
$6-3(i_1+i_2)-i_2=0$
......(i) $9-2i_1+i_2-3i_1=0$
.......(ii) Solving Eqs. (i) and (ii) we get,
$i_2=0.13 A$
Hence, the current in 1 Q resister is 0.13 A from Q to P

Solution Image