In the circuit element given here, if the potential at point B, i.e, VB=0, then the potentials of A and D are given as

Question

In the circuit element given here, if the potential at point B, i.e, VB=0, then the potentials of A and D are given as (A) VA=-1.5 V , VD=+2 V (B) VA=+1.5 V , VD=+2 V (C) VA=+1.5 V , VD=+0.5 V (D) VA=+1.5 V , VD=-0.5 V

Tardigrade Admin · Accepted Answer

Potential difference between A and B, VA-VB=1 × 1.5 ⇒ VA-0=1.5 V ⇒ V A=1.5 V Potential difference between B and C, VB-VC=1 × 2.5=2.5 V ⇒ VC=-2.5 V Now, Re q=5 Ω

Q. In the circuit element given here, if the potential at point $B$ , i.e, $V_{B} = 0$ , then the potentials of $A$ and $D$ are given as

$V_{A} = - 1.5 V, V_{D} = + 2 V$

$V_{A} = + 1.5 V, V_{D} = + 2 V$

$V_{A} = + 1.5 V, V_{D} = + 0.5 V$

$V_{A} = + 1.5 V, V_{D} = - 0.5 V$

Potential difference between $A$ and $B$ ,
$V_{A} - V_{B} = 1 \times 1.5$
$\Rightarrow V_{A} - 0 = 1.5 V \Rightarrow V_{A} = 1.5 V$
Potential difference between $B$ and $C$ ,
$V_{B} - V_{C} = 1 \times 2.5 = 2.5 V$
$\Rightarrow V_{C} = - 2.5 V$
Now, $R_{e q} = 5 Ω$

Q. In the circuit element given here, if the potential at point B, i.e, VB​=0, then the potentials of A and D are given as

VA​=−1.5V,VD​=+2V

VA​=+1.5V,VD​=+2V

VA​=+1.5V,VD​=+0.5V

VA​=+1.5V,VD​=−0.5V