Thank you for reporting, we will resolve it shortly
Q.
In the circuit element given here, if the potential at point $B$, i.e, $V_{B}=0$, then the potentials of $A$ and $D$ are given as
Current Electricity
Solution:
Potential difference between $A$ and $B$,
$V_{A}-V_{B}=1 \times 1.5$
$\Rightarrow V_{A}-0=1.5 V \Rightarrow V _{A}=1.5 V$
Potential difference between $B$ and $C$,
$V_{B}-V_{C}=1 \times 2.5=2.5\, V $
$\Rightarrow V_{C}=-2.5 \,V$
Now, $R_{e q}=5\, \Omega$
