In the circuit below, the potential difference between A and B is

Question

In the circuit below, the potential difference between A and B is <img class="img-fluid question-image" alt="Question" src="https://cdn.tardigrade.in/q/nta/p-vbcxpfair7plopog.jpg" /> (A) 10 V (B) 20 V (C) 30 V (D) 40 V

Tardigrade Admin · Accepted Answer

∴ V1=(((15/4)/1 + (15)4))× 190 =(15/19)× 190=150 V ⇒ V2=(190 - 150)V=40V Now, Solution

So, the potential difference between A and B will be, VA B=((1/1 + 3))× 40 =(1/4)× 40=10V

Q. In the circuit below, the potential difference between $A$ and $B$ is

$10 V$

$20 V$

$30 V$

$40 V$

$∴ V_{1} = (\frac{\frac{15}{4}}{1 + \frac{15}{4}}) \times 190$
$= \frac{15}{19} \times 190 = 150 V$
$\Rightarrow V_{2} = (190 - 150) V = 40 V$
Now,

So, the potential difference between $A$ and $B$ will be,
$V_{A B} = (\frac{1}{1 + 3}) \times 40$
$= \frac{1}{4} \times 40 = 10 V$

Q. In the circuit below, the potential difference between A and B is

10V

20V

30V

40V