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Q. In the circuit below, the potential difference between $A$ and $B$ is
Question

NTA AbhyasNTA Abhyas 2022

Solution:

Solution
$\therefore \, \, V_{1}=\left(\frac{\frac{15}{4}}{1 + \frac{15}{4}}\right)\times 190$
$=\frac{15}{19}\times 190=150 \, V$
$\Rightarrow \, V_{2}=\left(190 - 150\right)V=40V$
Now,
Solution
So, the potential difference between $A$ and $B$ will be,
$V_{A B}=\left(\frac{1}{1 + 3}\right)\times 40$
$=\frac{1}{4}\times 40=10V$